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【Java】 Springmvc 服务器端文件下载

作者:哲天 / 发布于2017/9/19/ 724

业务场景：点击下载后直接保存而不是打开解决代码：前端传入url

/**
     * 返回流
     * 
     * @param requestMap 请求参数
     * @param response 返回对象
     */ 
    @RequestMapping(value = "/file2Stream", method = RequestMethod.GET) 
    public void file2Stream(@Json Map<String, Object> requestMap, HttpServletResponse response) { 
        InputStream iStream = null; 
        OutputStream outStrem = null; 
        try { 
            String url = String.valueOf(requestMap.get("url")); 
            iStream = getFileStream(url); 
            String fileName = String.valueOf(requestMap.get("fileName")); 
            fileName = new String(fileName.getBytes(), "ISO8859-1"); 
            response.setCharacterEncoding("utf-8"); 
            response.setContentType("multipart/form-data"); 
            response.setHeader("Content-Disposition", "attachment;filename=\"" + fileName + "\""); 
            outStrem = response.getOutputStream(); 
            outStrem.write(StreamUtils.getBytes(iStream)); 
            outStrem.flush(); 
        } catch (Exception e) { 
            LOG.error("ProductSalesRecommendController.file2Stream  error | ({})", e); 
        }finally { 
            if(iStream != null){ 
                try { 
                    iStream.close(); 
                    iStream = null; 
                } catch (IOException e) { 
                    LOG.error("file2Stream.InputStream.close  error | ({})", e); 
                } 
            } 
            if(outStrem != null){ 
                try { 
                    outStrem.close(); 
                    outStrem = null; 
                } catch (IOException e) { 
                    LOG.error("file2Stream.OutputStream.close  error | ({})", e); 
                } 
            } 
        } 
    }

/**
     * HttpClient获取网络路径的文件流
     * 
     * @param url 链接字符串
     * @return InputStream
     * @throws IllegalStateException
     * @throws IOException
     */ 
    private InputStream getFileStream(String url) 
            throws IllegalStateException, IOException { 
        InputStream inStream = new URL(url).openStream(); 
        return inStream; 
    }

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