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【CSharp】获取相同概率随机数

作者:clark-lee / 发布于2014/1/22/ 432

算法原理跟二分查找的过程有点像。一枚硬币抽中正、反面的概率是一样，当抽样的次数无限增多，抽中的概率是50%。

public partial class MainWindow : Window
  {
    string s;
    int number;
    public MainWindow()
    {
      InitializeComponent();
    }
    public int getRandom()
    {
      //string[] arr = new string[5] { "我们", "是", "一", "个","团队" };

      Random r = new Random();
      int num = 2;
      int choose = r.Next(num);
      return choose;
      //MessageBox.Show(arr[choose].ToString());
    }
    public string GRandom(int n)
    {
      //if()
      if (n == 0)
      {
        //s = getRandom() + s;
        //System.Threading.Thread.Sleep(1);
        return s;
      }
      if (n % 2 == 0)
      {
        n = n / 2;

      }
      else
      {
        n = (n - 1) / 2;
        //s = getRandom() + s;
      }
      s = getRandom() + s;
      System.Threading.Thread.Sleep(20);
      GRandom(n);
      //System.Threading.Thread.Sleep(1);
      return s;
    }
    public Int32 Estimate(int n)
    {
      string num = GRandom(n);
      number = Convert.ToInt32(num, 2);
      if (number > n - 1)
      {
        //num = "";
        s = "";
        Estimate(n);
      }
      //else
      return number;
    }
    private void Button_Click(object sender, RoutedEventArgs e)
    {
      for (int i = 0; i < 100; i++)
      {
        label1.Content += Estimate(200) + ";";
        s = "";
      }
    }
  }

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