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【C】马踏棋盘

作者:卖姑娘的小火柴 / 发布于2014/9/10/ 397

8乘8的64个方格，按照马走棋的规则移动，利用1-64个数字标注马走的路径


	#include "stdio.h"
	#define X 8
	#define Y 8
	int chess[X][Y];
	
	int nextxy(int *x,int *y,int count) /*找到基于x,y位置的下一个可走的位置*/
	{
	 switch(count)
	 {
	 case 0: if(*x+2<=X-1 && *y-1>=0 && chess[*x+2][*y-1]==0) {*x =*x+2;*y = *y-1;return 1; } break;
	 case 1: if(*x+2<=X-1 && *y+1<=Y-1 && chess[*x+2][*y+1]==0) {*x = *x+2; *y = *y+1 ;
	return 1;}break;
	 case 2: if(*x+1<=X-1 && *y-2>=0 && chess[*x+1][*y-2]==0) {*x = *x+1; *y = *y-2; return 1;} break;
	 case 3: if(*x+1<=X-1 && *y+2<=Y-1 && chess[*x+1][*y+2]==0) {*x = *x+1; *y = *y+2;
	return 1;}break;
	 case 4: if(*x-2>=0 && *y-1>=0 && chess[*x-2][*y-1]==0) {*x = *x-2; *y = *y-1; return 1;} break;
	 case 5: if(*x-2>=0 && *y+1<=Y-1 && chess[*x-2][*y+1]==0){*x = *x-2; *y = *y+1; return 1;} break;
	 case 6:if(*x-1>=0 && *y-2>=0 && chess[*x-1][*y-2]==0) {*x = *x-1; *y = *y-2;return 1;}break;
	 case 7: if(*x-1>=0 && *y+2<=Y-1 && chess[*x-1][*y+2]==0) {*x = *x-1; *y = *y+2;
	return 1;}break;
	 default: break ;
	 }
	 return 0;
	}
	
	int TravelChessBoard(int x,int y,int tag) /*深度优先搜索地"马踏棋盘"*/
	{
	 int x1 = x, y1 = y, flag = 0,a,b ,count = 0 ;
	 chess[x][y] = tag;
	 if(tag == X*Y) { return 1;}
	 flag = nextxy(&x1,&y1,count);
	 while(flag == 0 && count <7){
	 count = count + 1;
	 flag = nextxy(&x1,&y1,count);
	 }
	 while(flag ){
	 if(TravelChessBoard(x1,y1,tag+1))return 1;
	 x1 = x;y1 = y;
	 count = count +1;
	 flag = nextxy(&x1,&y1,count); /*寻找下一个(x,y)*/
	 while(flag == 0 && count <7){ /*循环地寻找下一个(x,y)*/
	 count = count + 1;
	 flag = nextxy(&x1,&y1,count);
	 }
	 }
	 if(flag == 0)
	 chess[x][y] = 0;
	 return 0;
	}
	main()
	{
	 int i,j;
	 for(i=0;i<X;i++)
	 for(j=0;j<Y;j++)
	 chess[i][j] = 0;
	 if(TravelChessBoard(2,0,1)) {
	 for(i=0;i<X;i++) {
	 for(j=0;j<Y;j++)
	 printf("%d ",chess[i][j]);
	 printf("\n");
	 }
	 printf("The horse has travelled the chess borad\n");
	 }
	 else
	 printf("The horse cannot travel the chess board\n");
	 getche();
	}

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