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【CSharp】用HTTP协议发送、接收数据

作者:dezai / 发布于2014/7/23/ 756


	/// <summary>
	 /// post给定的url并获取返回的数据
	 /// </summary>
	 /// <param name="url"></param>
	 /// <param name="timeout"></param>
	 /// <returns></returns>
	 private string GetPostResult(string url, string strXml, int timeout)
	 {
	 string result;
	 try
	 {
	 strXml = strXml.Remove(0, strXml.IndexOf("<"));
	 //将数据以数据流方式提交到网关
	 WebRequest myWebRequest = WebRequest.Create(url);
	 myWebRequest.Method = "POST";
	 myWebRequest.Timeout = timeout;
	 //myWebRequest.ContentType = "application/x-www-form-urlencoded";

	 byte[] data = Encoding.Unicode.GetBytes(strXml);
	 myWebRequest.ContentLength = data.Length;
	 //添加Request.ContentType,否则对方可能无法接收
	 myWebRequest.ContentType = "text/xml";
	 myWebRequest.GetRequestStream().Write(data, 0, data.Length);

	
	 HttpWebResponse rep2 = (HttpWebResponse)myWebRequest.GetResponse();

	
	 //获取返回的数据
	 //WebResponse myWebResponse = myWebRequest.GetResponse();
	 StreamReader sr = new StreamReader(rep2.GetResponseStream());
	 result = sr.ReadToEnd();
	 result = result.Replace("/r/n", "");
	 sr.Close();
	 }
	 catch (Exception e)
	 {
	 System.Diagnostics.Debug.Print(e.ToString());
	 result = "error";
	 }
	 return result;
	 }

	接收：

	 XmlDocument xmlDoc = new System.Xml.XmlDocument();
	 byte[] data = new byte[Request.InputStream.Length];
	 Request.InputStream.Read(data, 0, (int)Request.InputStream.Length);

	string orderXml = Encoding.Unicode.GetString(data);
	 Request.InputStream.Close();
	 orderXml = Server.HtmlDecode(orderXml);
	 xmlDoc.LoadXml(orderXml);

试试其它关键字

　HTTP协议　　接收数据　　发送数据　

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