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【Java】 java 代码点到线段的最短距离

作者:Dezai.CN / 发布于2012/6/18/ 615

点到线段的最短距离

<div>
// 点到直线的最短距离的判断 点（x0,y0） 到由两点组成的线段（x1,y1） ,( x2,y2 )
<strong>private</strong> <strong>double</strong> pointToLine(<strong>int</strong> x1, <strong>int</strong> y1, <strong>int</strong> x2, <strong>int</strong> y2, <strong>int</strong> x0,
<strong>int</strong> y0) {
<strong>double</strong> space = 0;
<strong>double</strong> a, b, c;
a = lineSpace(x1, y1, x2, y2);// 线段的长度
b = lineSpace(x1, y1, x0, y0);// (x1,y1)到点的距离
c = lineSpace(x2, y2, x0, y0);// (x2,y2)到点的距离
<strong>if</strong> (c <= 0.000001 || b <= 0.000001) {
space = 0;
<strong>return</strong> space;
}
<strong>if</strong> (a <= 0.000001) {
space = b;
<strong>return</strong> space;
}
<strong>if</strong> (c * c >= a * a + b * b) {
space = b;
<strong>return</strong> space;
}
<strong>if</strong> (b * b >= a * a + c * c) {
space = c;
<strong>return</strong> space;
}
<strong>double</strong> p = (a + b + c) / 2;// 半周长
<strong>double</strong> s = Math.<em>sqrt</em>(p * (p - a) * (p - b) * (p - c));// 海伦公式求面积
space = 2 * s / a;// 返回点到线的距离（利用三角形面积公式求高）
<strong>return</strong> space;
}

// 计算两点之间的距离
<strong>private</strong> <strong>double</strong> lineSpace(<strong>int</strong> x1, <strong>int</strong> y1, <strong>int</strong> x2, <strong>int</strong> y2) {
<strong>double</strong> lineLength = 0;
lineLength = Math.<em>sqrt</em>((x1 - x2) * (x1 - x2) + (y1 - y2)
* (y1 - y2));
<strong>return</strong> lineLength;

}
</div>

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　点到线段的最短距离　

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