后台给某网址传递参数，并接收返回值代码,Asp.Net代码库,德仔网

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【Asp.Net】后台给某网址传递参数，并接收返回值

作者:Dezai.CN / 发布于2013/5/9/ 446


	/// <summary>
	 /// POST提交XML文件获取返回数据
	 /// </summary>
	 /// <param name="url">网址</param>
	 /// <param name="strPost">XML数据</param>
	 /// <returns></returns>
	 private string PostXml(string url, string strPost)
	 {
	 string result = "";

	 StreamWriter myWriter = null;

	 HttpWebRequest objRequest = (HttpWebRequest)WebRequest.Create(url);
	 objRequest.Method = "POST";
	 objRequest.ContentLength = strPost.Length;
	 objRequest.ContentType = "text/xml";//提交xml
	 //objRequest.ContentType = "application/x-www-form-urlencoded";//提交表单
	 try
	 {
	 myWriter = new StreamWriter(objRequest.GetRequestStream());
	 myWriter.Write(strPost);
	 }
	 catch (Exception e)
	 {
	 return e.Message;
	 }
	 finally
	 {
	 myWriter.Close();
	 }

	 HttpWebResponse objResponse = (HttpWebResponse)objRequest.GetResponse();
	 using (StreamReader sr = new StreamReader(objResponse.GetResponseStream()))
	 {
	 result = sr.ReadToEnd();
	 sr.Close();
	 }
	 return result;
	 }

	 /// <summary>
	 /// Post提交获取返回数据
	 /// </summary>
	 /// <param name="url">网址</param>
	 /// <returns></returns>
	 protected string GetWebContent(string url)
	 {
	 Stream outstream = null;
	 Stream instream = null;
	 StreamReader sr = null;
	 HttpWebResponse response = null;
	 HttpWebRequest request = null;
	 // 要注意的这是这个编码方式，还有内容的Xml内容的编码方式
	 Encoding encoding = Encoding.GetEncoding("UTF-8");
	 byte[] data = encoding.GetBytes(url);

	 // 准备请求,设置参数
	 request = WebRequest.Create(url) as HttpWebRequest;
	 request.Method = "POST";
	 //request.ContentType = "text/plain";
	 request.ContentLength = data.Length;

	 outstream = request.GetRequestStream();
	 outstream.Write(data, 0, data.Length);
	 outstream.Flush();
	 outstream.Close();
	 //发送请求并获取相应回应数据

	 response = request.GetResponse() as HttpWebResponse;
	 //直到request.GetResponse()程序才开始向目标网页发送Post请求
	 instream = response.GetResponseStream();
	 sr = new StreamReader(instream, encoding);
	 //返回结果网页(html)代码

	 string content = sr.ReadToEnd();
	 return content;
	 }

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