把罗马数的字符串转成阿拉伯数代码,C代码库,德仔网

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【C】把罗马数的字符串转成阿拉伯数

作者:Dezai.CN / 发布于2011/4/26/ 696

#include <iostream>
#include <cstring>
using namespace std;
// prototype for function
int romano_dec();
int main(int argc, char *argv[])
{
romano_dec();
system("PAUSE");
return EXIT_SUCCESS;
}
int romano_dec()
{
char roman_num[10];
cout << "Por favor ingrese un numero romano: ";
cin >> roman_num;
int len = strlen(roman_num);
int number = 0;
int counter = 0;
int b4sum = 0;
int sum = 0;
for (counter = len; counter >= 0; counter--)
{
if (roman_num[counter] == 'M' || roman_num[counter] == 'm')
number = 1000;
else if (roman_num[counter] == 'D' || roman_num[counter] == 'd')
number = 500;
else if (roman_num[counter] == 'C' || roman_num[counter] == 'c')
number = 100;
else if (roman_num[counter] == 'L' || roman_num[counter] == 'l')
number = 50;
else if (roman_num[counter] == 'X' || roman_num[counter] == 'x')
number = 10;
else if (roman_num[counter] == 'V' || roman_num[counter] == 'v')
number = 5;
else if (roman_num[counter] == 'I' || roman_num[counter] == 'i')
number = 1;
else
number = 0;
if (b4sum > number)
sum = b4sum - number;
else
sum = sum + number;
b4sum = number;
}
cout << "El resultado es: " ;
cout << sum << endl;
}

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　转成阿拉伯数　

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