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【Java】移位运算

作者:Dezai.CN / 发布于2011/12/1/ 549

<div> public static void main(String args[]) {
 byte[] bytes = new byte[] { 0x1, 0x00, 0x00 };
 BigInteger bi = new BigInteger(bytes);
 System.out.println(bi);
 //右移一位
 System.out.println("after shift right is " + bi.shiftRight(1));
 //左移3位
 System.out.println("after shift left is " + bi.shiftLeft(3));
 //翻转第三位，既如果第三位(0 based)为0，则翻转为1，反之翻转为0.
 //翻转之前：10000000000000000
 //翻转之后：10000000000001000
 bi = bi.flipBit(3);
 System.out.println("after flip is " + bi);
 //将第三位的bit清0
 //clear之前：10000000000001000
 //clear之后：10000000000000000
 bi = bi.clearBit(3);
 System.out.println("after clear is " + bi);
 //将第三位设置为1
 //set之前：10000000000000000
 //set之后：10000000000001000
 bi = bi.setBit(3);
 System.out.println("after set is " + bi);
 System.out.println("The binary result for bi is " + bi.toString(2));
 System.out.println("The test result for BIT 2 is " + bi.testBit(2));
 System.out.println("The test result for BIT 3 is " + bi.testBit(3));
 }
 /* 输出结果如下：
 65536
 after shift right is 32768
 after shift left is 524288
 after flip is 65544
 after clear is 65536
 after set is 65544
 The binary result for bi is 10000000000001000
 The test result for BIT 2 is false
 The test result for BIT 3 is true
 */</div>

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